11607. ASCII Art

You are given a matrix A of size h ? w consisting of integers from 0 to 26. The element located in the i-th row from the top and the j-th column from the left is denoted by A_i,j.

Let s₁, s₂, …, s_h be strings of length w, defined as follows:

• The j-th character of the string s_i is a dot (.), if A_i,j = 0.
• Otherwise, it is the A_i,j-th uppercase letter of the English alphabet (for example, the 4-th letter is D).

Print the strings s₁, s₂, …, s_h, one per line.

Input. The first line contains two integers h and w – the height and width of the matrix A.

The next h lines contain w integers each – the elements of the matrix A.

Output. Print h lines. In the i-th line print the string s_i.

Sample input 1	Sample output 1
2 3 0 1 2 0 0 3	.AB ..C
Sample input 2	Sample output 2
3 3 24 0 0 0 25 0 0 0 26	X.. .Y. ..Z

SOLUTION

two-dimensional array

Algorithm analysis

You are given a matrix of size h ? w. Each number should be replaced with a character:

· if the number is 0, print a dot.

· if the number is between 1 and 26, print the corresponding uppercase letter of the English alphabet.

Let A_i,j = x. It is known that the value x = 1 corresponds to the letter ‘A’, and the value x = 26 corresponds to the letter ‘Z’. Therefore, if A_i,j = x, the character to print in the corresponding position is x + ‘A’ – 1.

Algorithm implementation

Read the dimensions of the matrix.

scanf("%d %d", &h, &w);

Iterate through the matrix, and for each value x, print the corresponding character.

for (i = 0; i < h; i++)

{

for (j = 0; j < w; j++)

{

scanf("%d", &x);

if (x == 0) printf(".");

else printf("%c", x + 'A' - 1);

}

printf("\n");

}