An array of
integers is given. Print all elements that are greater than their previous
element.
Input. The first line
contains the integer n – the number of elements in the array.
The second line contains n integers. Each number does not
exceed 100 in absolute value.
Output. Print all elements
of the array that are strictly greater than the previous element.
|
Sample input |
Sample output |
|
7 14 17 16 3 7 19 9 |
16 7 17 19 |
loops
Read the
input sequence of numbers and store it in an array. Then, using a loop, print all elements that are greater than their previous
element.
Algorithm implementation
Declare an array.
int m[101];
Read the number of input elements n.
scanf("%d",&n);
Read the input array.
for (i = 0; i < n; i++)
scanf("%d", &m[i]);
Print all
elements of the array that are strictly greater than the previous one.
for (i = 1; i < n; i++)
if (m[i] > m[i
- 1]) printf("%d ", m[i]);
Java implementation
import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int n = con.nextInt();
int m[] = new int[n];
for(int i = 0; i < n; i++)
m[i] = con.nextInt();
for (int i = 1; i < n; i++)
if (m[i] > m[i-1]) System.out.print(m[i] + " ");
System.out.println();
con.close();
}
}
Python implementation
Read the input data.
n = int(input())
lst = list(map(int, input().split()))
Print all
elements of the array that are strictly greater than the previous one.
for i in range(1,n):
if lst[i] >
lst[i-1]: print(lst[i], end = " ")