One integer n is given. Print whether it is positive, negative, or equal to 0.
Input. One integer n, no more than 109 by absolute value.
Output. Print “Positive”, “Negative” or “Zero” depending on the value of n.
|
Sample input 1 |
Sample output 1 |
|
45 |
Positive |
|
|
|
|
Sample input 2 |
Sample output 2 |
|
0 |
Zero |
conditional
statement
Use a conditional statement to find the sign of the
number.
Algorithm
implementation
Read the input value of n.
scanf("%d",&n);
Determine the sign of the number: positive, negative or zero.
if (n > 0) puts("Positive");
else
if (n < 0) puts("Negative");
else
puts("Zero");
Algorithm
implementation – switch
#include <stdio.h>
int n;
int main(void)
{
scanf("%d", &n);
switch (n > 0)
{
case 1:
puts("Positive");
break;
case 0:
switch (n < 0)
{
case 1:
puts("Negative");
break;
default:
puts("Zero");
}
}
return 0;
}
Java implementation
import java.util.*;
public class Main
{
public static void main(String []args)
{
Scanner con = new Scanner(System.in);
int n = con.nextInt();
if (n > 0) System.out.println("Positive"); else
if (n < 0) System.out.println("Negative"); else
System.out.println("Zero");
con.close();
}
}
Python implementation
Read the input value of n.
n = int(input())
Determine the sign of the number: positive, negative or zero.
if n > 0: print("Positive")
elif n < 0: print("Negative")
else: print("Zero")