8611. Water and ice

The bucket was filled with water and placed outside. The outside air temperature is t degrees. Print “Water” if t is positive, and “Ice” otherwise.

Input. One integer t (-10⁹ ≤ t ≤ -10⁹).

Output. Print “Water” if t is positive, and “Ice” if t is zero or negative.

Sample input 1	Sample output 1
3	Water
Sample input 2	Sample output 2
-6	Ice

SOLUTION

conditional statement

Algorithm analysis

To solve this problem, use a conditional statement.

Algorithm implementation

Read the input temperature value t.

scanf("%d", &t);

Based on the value of t, print the corresponding result.

if (t > 0)

printf("Water\n");

else

printf("Ice\n");

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int t = con.nextInt();

if (t > 0)

System.out.println("Water");

else

System.out.println("Ice");

con.close();

}

}

Python implementation

Read the input temperature value t.

t = int(input())

Based on the value of t, print the corresponding result.

if t > 0:

print("Water")

else:

print("Ice")