8873. One – digit number

Given an integer n. Print “Ok” if n consists of a single digit, and “No” otherwise.

Input. One integer n (|n| ≤ 10⁹).

Output. Print “Ok” if n is a single-digit number, and “No” otherwise.

Sample input 1	Sample output 1
7	Ok
Sample input 2	Sample output 2
-77	No

SOLUTION

conditional statement

Algorithm analysis

The input number n can be negative. The absolute value of n consists of a single digit. In other words, the inequality -9 ≤ n ≤ 9 must hold.

Algorithm implementation

Read the input value of n.

scanf("%d", &n);

Print the answer.

if (n > -10 && n < 10) puts("Ok");

else puts("No");

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int n = con.nextInt();

if (n > -10 && n < 10) System.out.println("Ok");

else System.out.println("No");

con.close();

}

}

Python implementation

Read the input value of n.

n = int(input())

Print the answer.

if n > -10 and n < 10: print("Ok")

else: print("No")

Python implementation – 2

Read the input value of n.

n = int(input())

Print the answer.

if -10 < n < 10: print("Ok")

else: print("No")