9405. Professor and balloons

For the celebration, the Professor bought balloons of three colors: blue, red, and yellow. In total, he bought n balloons. The number of yellow and blue balloons is a, and the number of red and blue balloons is b.

Determine how many blue, red, and yellow balloons the Professor bought.

Input. Three positive integers n, a, b.

Output. Print in one line the number of blue, red, and yellow balloons bought by the Professor.

Sample input	Sample output
10 6 8	4 4 2

SOLUTION

mathematics

Algorithm analysis

Let blue, red and yellow denote the numbers of blue, red, and yellow balloons, respectively. According to the problem statement, the following equalities hold:

· yellow + blue = a (yellow and blue balloons);

· red + blue = b (red and blue balloons);

· blue + red + yellow = n (the total number of balloons)

From the system of equations, we find the number of balloons of each color:

· red = n – a;

· yellow = n – b;

· blue = a + b – n;

Algorithm implementation

Read the input data.

scanf("%d %d %d", &n, &a, &b);

Compute and print the answer.

blue = a + b - n;

red = n - a;

yellow = n - b;

printf("%d %d %d\n", blue, red, yellow);

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int n = con.nextInt();

int a = con.nextInt();

int b = con.nextInt();

int blue = a + b - n;

int red = n - a;

int yellow = n - b;

System.out.println(blue + " " + red + " " + yellow);

con.close();

}

}

Python implementation

Read the input data.

n, a, b = map(int,input().split())

Compute and print the answer.

blue = a + b - n;

red = n - a;

yellow = n - b;

print(blue, red, yellow);